Explain giving reasons for the following : (a) Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation. (b) The stopping potential (V 0) varies linearly with the frequency (ν) of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces.
Learn MorePhotoelectric cells are devices that generate a photoelectric current when light falls on their surface, allowing for the direct measurement of illumination. They include three types: …
Learn MoreA photocell or photoresistor is a sensor that changes its resistance when light shines on it. The resistance generated varies depending on the light striking at his surface. A high intensity of light incident on the surface will cause a lower resistance, whereas a lower intensity of light will cause higher resistance.
Learn MoreIn combustion TPV systems with radiation densities as high as ≈ 50 W cm-2 at the emitter surface and the close proximity of PV cells to the emitter, the irradiation density on the photocells can be 5–100 times higher than that due to solar illumination (∼ 0.1 W cm-2).
Learn MoreIdentify the pairs of curves that correspond to different materials but same intensity of incident radiation. View Solution. Q4. The given graph shows the variations of photo-electric current (I) versus applied voltage (V) for two different photosensitive materials and for two different intensities of the incident radiations. Identify the pairs ...
Learn MoreIf the intensity of radiation incident on a photocell be increased four times, then the number of photoelectrons and the energy of photoelectrons emitted respectively become. A four times, doubled B doubled, remains unchanged
Learn MoreIdentify the pairs of curves that correspond to different materials but same intensity of incident radiation. View Solution. Q3. Draw graphs showing variation of photoelectric current with applied voltage for two incident radiations of equal frequency and different intensities. Mark the graph for the radiation of higher intensity.
Learn MoreExplain giving reasons for the following :a Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation.b The stopping potential V 0 varies linearly with the frequency v of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces.c Maximum kinetic energy of the …
Learn MoreThe current–voltage characteristics of investigated silicon photocells are built depending on their quantity (36, 48, 60, 72), incident solar radiation intensity (1000, …
Learn MoreExplain how does (i) photoelectric current and (ii) kinetic energy of the photoelectrons emitted in a photocell vary if the frequency of incident radiation is doubled, but keeping the intensity same? Show the graphical variation in the above two cases.
Learn MoreThe correct answer is Since the number of photoelectrons emitted is directly proportional to the intensity of incident radiation, the number of photoelectrons emitted becomes four times.The energy . courses. study material. results. more. need help? talk to experts. talk to experts. 7996668865. Questions If the intensity of radiation incident ...
Learn MoreFor the purposes of this article light consists of electromagnetic radiation in the visible (wavelengths approximately 400-800 nm), near infrared [1] ... This is because it is generally hard to predict the light intensity at the photocell in a given system, and in many cases it is also hard to determine the photocell''s sensitivity to the actual ...
Learn MoreIf the intensity of radiation in a photocell is increased, how does the stopping potential vary? asked Jul 11 in Physics by ShaileshTiwari (60.5k points) dual nature of radiation and matter; class-12; 0 votes. 1 answer. The frequency (v) of incident radiation is greater than threshold frequency (v0) in a photocell. How will the stopping potential
Learn MoreThe photoelectric current will increase with the increase of intensity of radiation as an increasing number of photons, the electrons get ejected which is directly proportional to the intensity of light. ... If the intensity of the incident radiation in a photocell is increased, how does the stopping potential very? asked Jun 14, 2019 in ...
Learn MoreEfficiency of GaAs Photocells in Low Light Conditions. Gallium Arsenide (GaAs) photocells excel in environments with low light conditions. GaAs is a semiconductor material that has a narrow bandgap, allowing it to efficiently convert light into electrical energy, even in situations where light intensity is minimal.
Learn MoreNeutral filter to vary light intensity; INTRODUCTION. The energy quantization of electromagnetic radiation in general, and of light in particular, is expressed in the famous relation begin{eqnarray} E &=& hf, label{eqn_1} end{eqnarray} where (E) is the energy of the radiation, (f) is its frequency, and (h) is Planck''s constant (6.63× ...
Learn MoreThe photoelectric effect has three important characteristics that cannot be explained by classical physics: (1) the absence of a lag time, (2) the independence of the kinetic …
Learn MoreIf the intensity of the radiation on a photocell be increased four times, then the number of photoelectrons and the energy of photoelectrons emitted respectively become . View Solution. Q4. The intensity of incident radiation on a photocell is increased to 4times. Then the number of photoelectrons emitted per second will be
Learn MoreHow many of the following statements are correct? (a) K.E. of photoelectron does not depend upon the wavelength of incident radiation (b) Photoelectric current depends on intensity of incident radiation and not on frequency
Learn MoreEffect of Doubling the Intensity of Incident Radiation: - (i) Stopping Potential (V₀): - The stopping potential is determined by the maximum kinetic energy of the emitted electrons and is given by: ( eV₀ = K.E. Rightarrow V₀ = frac{K.E.}{e} ) - Doubling the intensity of the incident radiation increases the number of photons but does ...
Learn MoreThe photocurrent response obtained by increasing the aperture of the lead cover over the photocell showed a reduction of radiation intensity towards the boundary of the -ray beam. A second photocell of the same type gave a similar response, but the photocurrent values were reduced to one-third of the values obtained previously.
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